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The boiling point of a solution of 0.11 g of a substance in 15 g of ether was found to be 0.1 °C higher than that of pure ether. The molecular weight of the substance will be (K_b= 2.16 °K kgmol^-1)

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148

168

178

158

answer is B.

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Detailed Solution

$M = \frac{K_{b} \times w \times 1000}{{ΔT}_{b} \times W} = \frac{2.16 \times 0.11 \times 1000}{0.1 \times 15} = 158.4$

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