The bond angle and $\%$ of d-character in ${\mathrm{SF}}_6$ are

Sulphur hexafluoride involves ${\mathrm{sp}}^3{\mathrm{d}}^2$ hybridization and possesses octahedral geometry.

% of d-character

$=\frac{2\left(\text{ no of }\mathrm{d}\text{-orbitals }\right)}{6\text{ (total hybridised orbitals) }}$

Bond angle $={90}^{\circ }.$