The bond angle around O in ${\mathrm{CH}}_3\mathrm{OH}$ is

In this compound,  the carbon atom has a ${\mathbf{sp}}^{\mathbf{3}}$ hybridization and forms a
tetrahedral shape, it has bond angles of $109.5$ degrees with its bonding atoms. The bond angle is less than ${110}^0$. 

So, option C) is correct.