The bond angle in $H_{2} O$ is approximately $105^{\circ}$ while the bond angle in $H_{2} S$ is approximately $90^{\circ}$ . Which explanation best accounts for this difference?

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

$H - S$ bonds are longer than $H - S$ bonds,

S has d orbitals available for bonding, O does not

$H - S$ bonds are less polar than $H - O$ bonds.

O uses ${sp}^{3}$ hybrid orbitals for bonding, S uses its $3 p$ orbitals.

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

According to Drago's rule, in the following circumstances, it is not necessary to pay attention to an element's hybridization: Case 1: The centre atom of the molecule has at least one lone pair of electrons. Case 2: The centre atom can be made up of any of the elements from groups 13, 14, 15, or 16 or from the third to seventh period.

Hence, the correct answer is D.

Watch 3-min video & get full concept clarity