The bond angle in ${\mathrm{XeF}}_4$ molecule is

 The F-Xe-F bond angle in ${\mathrm{XeF}}_4$ ​ is 90 degrees. In ${\mathrm{XeF}}_4$ ​ molecule the Xenon is present at the center and fluorine atoms are directed toward four corners of a square. The geometry is square pyramidal.