The bond angle in ${XeF}_{4}$ molecule is

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$90^{0}$

$180 °$

$120 °$

$100 °$

answer is D.

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Detailed Solution

The F-Xe-F bond angle in ${XeF}_{4}$ is 90 degrees. In ${XeF}_{4}$ molecule the Xenon is present at the center and fluorine atoms are directed toward four corners of a square. The geometry is square pyramidal.

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