The bond cleavages during esterification reaction between
(A) = CH₃COOH and (B) C₂H₅OH

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C – O in A and O – H in A

C – O in A and O – H in B

O – H in B and O – H in A

C – O in B and O – H in A

answer is B.

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Detailed Solution

During esterification, first proton interact with O from -C=O part from carboxylic acid, this will creates a positive charge on O, which on resultant cleavage of C-O bond takes place in carboxylic acid. Hence, a positive charge is generated on C atom.

Later on, oxygen atom of alcohol interacts with positively charged C atom of carboxylic acid, this will creates a positive charge on O, which on resultant cleavage of O-H bond takes place in alcohol.

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