The bond dissociation energy of B – F in BF3 is 646 kJ mol–1. where as that of C – F in CF4 is 515 kJ mol–1. The correct reason for higher B – F bond dissociation energy as compared to that of C – F bond is

Significant pπ - pπ interaction between B and F in BF 3 whereas there is no possibility of such interaction between C and F in CF 4

The bond dissociation energy of B – F in BF3 is 646 kJ mol–1. where as that of C – F in CF4 is 515 kJ mol–1. The correct reason for higher B – F bond dissociation energy as compared to that of C – F bond is

Significant pπ - pπ interaction between B and F in BF 3 whereas there is no possibility of such interaction between C and F in CF 4

stronger σ bond between B and F in BF 3 as compared to that between C and F in CF 4

Significant pπ - pπ interaction between B and F in BF 3 whereas there is no possibility of such interaction between C and F in CF 4

Lower degree of pπ - pπ interaction between B and F in BF 3 than that between C and F in CF 4

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The bond dissociation energy of B – F in BF₃ is 646 kJ mol^–1. where as that of C – F in CF₄ is 515 kJ mol^–1. The correct reason for higher B – F bond dissociation energy as compared to that of C – F bond is

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stronger σ bond between B and F in BF₃ as compared to that between C and F in CF₄

Significant pπ - pπ interaction between B and F in BF₃ whereas there is no possibility of such interaction between C and F in CF₄

Lower degree of pπ - pπ interaction between B and F in BF₃ than that between C and F in CF₄

Smaller size of B-atom as compared to that of C-atom

answer is B.

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Detailed Solution

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$B - F,bond,order = frac{{2 + 1 + 1}}{3} = frac{4}{3} = 1.33$

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$large B.O; propto ;frac{1}{{B.L}}$

$large B.O; propto ;B.E$
In BF₃ due to back π-bonding the bond order is more and hence bond dissociation energy is more [646KJ/mole]
Where as in case of CF₄ there is no such back π-bond formation, hence the C - F bond order is less so bond dissociation energy for C - F bond is low [515KJ/mole]