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Q.

The bond dissociation enthalpy of X2 ΔHbond calculated from the given data is _______ kJ mol–1.
(Nearest integer)

M+X(s)M+(g)+X(g)ΔHlattice =800kJmol1M(s)M(g)ΔHsub =100kJmol1M(g)M+(g)+e(g)ΔHi=500kJmol1X(g)+e(g)X(g)ΔHeg =300kJmol1M(s)+12X2(g)M+X(s)ΔHf=400kJmol1

[Given : M+X is a pure ionic compound and X forms a diatomic molecule X2 is gaseous state]

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answer is 200.

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Detailed Solution

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ΔHf(MX)=ΔHsub(M)+ I.E. (M)+12[ B.E. (XX)] + EG(X) + L.E.(MX)  400=(100)+(500)+12( B.E. )+(300)+(800) B.E. =200kJmole1

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