The bond energy (Kcal/mole) of the carbon-carbon bond in ethylene is closest to

Bond energy quantity of energy required for breaking down the molecular bonds into free atoms.
Higher the bond energy, the more stable the molecule. 

C-C bond energy=348J/mol

$$\begin{gathered} =\frac{348}{4.2}\mathrm{kcal}/\mathrm{mol} \\ =82.85\mathrm{kcal}/\mathrm{mol} \\ \approx 100\mathrm{kcal}/\mathrm{mol}/ \end{gathered}$$

So, option A) 100 is correct.