The bond energy of $C = O$ if $Δ H_{f}^{\circ} ({CO}_{2}) = - 390 kJ$ , $Δ H_{sublimation}^{\circ}$ (Graphite)= 720 kJ, 0 = 0 bond energy = 490 kJ and resonance energy $({CO}_{2}) = 36 kJ$ :

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782 kJ

626 kJ

500 kJ

1564 kJ

answer is A.

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Detailed Solution

In the reaction we have,

$C (g r) + O_{2} (g) ⟶ {CO}_{2} (g)$

$Δ H_{f}^{\circ} (thee) = 720 + 490 - 2 x$

$\begin{array}{l} Δ H_{f}^{\circ} (\exp) - Δ H_{f}^{\circ} (theo) = - R \cdot E \\ - 390 - 1210 + 2 x = - 36 \end{array}$

$\Rightarrow x = 782$

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