The bond length in CO is 1.128 A∘. What will be the bond length of CO in Fe(CO)5?

Synergic bonding is generally observed in coordination compounds, where there is transfer of electrons from filled orbitals of metals to anti-binding of ligands. This strengthens the bond between metal and ligand. In Fe(CO)5, there is synergic bonding between Fe and CO, this increases the bond length between C=O, thereby bond order of C=O decreases. Among given options, only 1.158 A∘ is greater than the given bond length value of CO, 1.128 A∘.

The bond length in CO is 1.128 A∘. What will be the bond length of CO in Fe(CO)5?

Synergic bonding is generally observed in coordination compounds, where there is transfer of electrons from filled orbitals of metals to anti-binding of ligands. This strengthens the bond between metal and ligand. In Fe(CO)5, there is synergic bonding between Fe and CO, this increases the bond length between C=O, thereby bond order of C=O decreases. Among given options, only 1.158 A∘ is greater than the given bond length value of CO, 1.128 A∘.

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The bond length in $CO$ is $1 .128 \overset{\circ}{A} .$ What will be the bond length of $CO$ in $Fe (CO)_{5} ?$

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$1 .158 \overset{\circ}{A}$

$1.128 \overset{\circ}{A}$

$1 .108 \overset{\circ}{A}$

$1 .118 \overset{\circ}{A}$

answer is A.

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Detailed Solution

Synergic bonding is generally observed in coordination compounds, where there is transfer of electrons from filled orbitals of metals to anti-binding of ligands. This strengthens the bond between metal and ligand. In Fe(CO)₅, there is synergic bonding between Fe and CO, this increases the bond length between C=O, thereby bond order of C=O decreases. Among given options, only $1.158 \overset{\circ}{A}$ is greater than the given bond length value of CO, $1.128 \overset{\circ}{A} .$