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The bond length of HCl bond is $2.29 \times 10^{- 10} m$ . The percentage ionic character of HCl, if measured dipole moment is $6.226 \times 10^{- 30} cm$ , is

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20%

17%

50%

answer is C.

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Detailed Solution

$\begin{array}{rcl} μ_{cal .} & = & e \times d = 1.6 \times 10^{- 19} \times 2.29 \times 10^{- 10} \\ = & 3.664 \times 10^{- 29} Cm . \end{array}$

$\begin{array}{rcl} % of Ionic character & = & \frac{μ_{\exp .}}{μ_{cal .}} \times 100 \\ = & \frac{6.226 \times 10^{- 30}}{3.664 \times 10^{- 29}} \times 100 \\ = & 17 % \end{array}$

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