The bond order and magnetic behavior of ${\mathrm{O}}_2^{-}$ ion are, respectively :
 

$$\begin{gathered} \begin{array}{rl} & {\mathrm{O}}_2^{-}={\left({\sigma }_{1\mathrm{s}}\right)}^2{\left({\sigma }_{1\mathrm{s}}^{\ast }\right)}^2{\left({\sigma }_{2\mathrm{s}}\right)}^2{\left({\sigma }_{2\mathrm{s}}^{\ast }\right)}^2{\left({\sigma }_{2\mathrm{pz}}\right)}^2({\mathrm{\pi }}_{2\mathrm{px}}^2={\mathrm{\pi }}_{2\mathrm{py}}^2)({\mathrm{\pi }}_{2\mathrm{px}}^{*2}={\mathrm{\pi }}_{2\mathrm{py}}^{*1})\end{array} \\ \text{Bond order}=\frac{10-7}{2}=1.5 \\ \text{and paramagnetic} \end{gathered}$$

Hence, correct option is :(D) 1.5 and paramagnetic