The bond order in $\text{ NO }$ is $2.5$ while that in ${\mathrm{NO}}^{+}$ is $3$. Which of the following statements is true for these two species?

Going from NO to ${\mathrm{NO}}^{+}$ results in stronger bonds and shorter bonds since the bond strength rises. No 0 π*antibonding electrons exist in ${\mathrm{NO}}^{+}$. 1 π* antibonding electron exists in NO. There are 2 π* antibonding electrons in NO.

Bond length in NO is greater than in ${\mathrm{NO}}^{+}$

$\text{ B.L. }\propto \frac{1}{\text{ B.O. }}$

Hence correct option is B.