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Q.
The bond order in species is
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a
2
b
1
c
3
d
4
answer is A.
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Detailed Solution
The bond order of O22- species can be determined using the molecular orbital theory. Let us analyze this step-by-step:
Electronic Configuration of O22-
The total number of electrons in O22- is 18. The molecular orbital configuration for O22- is as follows:
σ(1s)² σ*(1s)² σ(2s)² σ*(2s)² σ(2pz)² (π(2px)² = π(2py)²) (π*(2px)² = π*(2py)²)
Here, the σ orbitals represent bonding molecular orbitals, while σ* and π* orbitals represent anti-bonding molecular orbitals.
Calculation of Bond Order
Bond order is calculated using the formula:
Bond Order = (Nb - Na) / 2
- Nb: Number of bonding electrons
- Na: Number of anti-bonding electrons
For O22-:
- Number of bonding electrons (Nb) = 10
- Number of anti-bonding electrons (Na) = 8
Substituting these values into the formula:
Bond Order = (10 - 8) / 2 = 1
Interpretation of Bond Order
The bond order of O22- is 1. This indicates that the species has a single bond between the two oxygen atoms. The species is also diamagnetic because all electrons are paired in its molecular orbitals.
Importance of Bond Order in O22-
The bond order of O22- helps in understanding the stability and bonding characteristics of this species. A bond order of 1 signifies that O22- is less stable compared to O2 or O2+, which have higher bond orders.
The concept of bond order of O22- is crucial in molecular orbital theory as it provides insights into the electronic arrangement and magnetic properties of the molecule.