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The bond orders of ${He}_{2}^{+}$ and ${He}_{2}$ are respectively

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0.1

$\frac{1}{2}, 0$

1.0

$\frac{1}{2}, 1$

answer is A.

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Detailed Solution

${He}_{2} (4 e^{-}) = σ 1 s^{2} σ^{*} 1 s^{2} Bond order = \frac{2 - 2}{2} = 0 {He}_{2}^{+} (3 e^{-}) = σ 1 s^{2} σ^{*} 1 s^{1} Bond order = \frac{2 - 1}{2} = 0.5$

Hence , the correct option (A).

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