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The Boolean expression for the given circuit is

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$A . B$

$A + B$

answer is A.

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Detailed Solution

$Y = \bar{A \cdot B} + \bar{\bar{A} + B} = \bar{A} + \bar{B} + \bar{\bar{A}} \cdot \bar{\bar{B}}$

$= \bar{A} + \bar{B} + A \cdot \bar{B} = \bar{A} + (1 + A) \bar{B} = \bar{A} + \bar{B} = \bar{A \cdot B}$

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