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The Born-Haber cycle for $K C l$ is evaluated with the following data: $Δ_{f} H^{Θ}$ for $K C l = - 436.7 k j m o l^{- 1}; Δ_{s u b} H^{Θ}$ for $K = 89.2 k J m o l^{- 1}; Δ_{i o n i z a t i o n} H^{Θ} f o r K = 419.0 k j m o l^{- 1}$
$Δ_{e l e c t r o n g a i n} H^{Θ} f o r C l_{(g)} = - 348.6 k j m o l^{- 1} Δ_{b o n d} H^{Θ} f o r C l_{2} = 243.0 k j m o l^{- 1}$
The magnitude of lattice enthalpy of $K C l$ in $k j m o l^{- 1}$ is ______. (Nearest integer)

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answer is 718.

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Detailed Solution

$- U = Δ H_{f} - {+ S E + I E + \frac{1}{2} (B E) - E A} = - 436.7 - (89.2 + 419.0 + \frac{1}{2} (243.0) - 348.6) = - 717.8 k j / m o l$

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