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The bottom of a beaker containing a liquid appears to rise by 4 cm. On increasing the depth of the liquid by 12 cm, the bottom appears to rise by 7 cm. The refractive index of the liquid is

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$5/4$

$9/8$

$3/2$

$4/3$

answer is D.

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Detailed Solution

$4 = (1 - \frac{1}{μ}) x$

$7 = (1 - \frac{1}{μ}) (x + 12)$

$\Rightarrow \frac{3}{12} = (1 - \frac{1}{μ})$

$\frac{1}{μ} = 1 - \frac{3}{12} = \frac{9}{12} = \frac{3}{4}$

$μ = \frac{4}{3}$

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