The brown ring complex compounds is formulated as $[F e {(H_{2} O)}_{5} (N O)] S O_{4}$ .The oxidation state of iron is

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Detailed Solution

The brown ring complex, represented as [Fe(H₂O)₅(NO)]SO₄, is a well-known coordination compound. When the brown ring complex dissolves in water, it dissociates into two distinct ions:

The cation: [Fe(H₂O)₅(NO)]²⁺
The anion: SO₄²⁻

To determine the oxidation state of iron (Fe) in the brown ring complex, we analyze the components in the cation [Fe(H₂O)₅(NO)]²⁺:

The nitric oxide ligand (NO) in the brown ring complex has an oxidation state of +1.
Water molecules (H₂O) are neutral ligands and do not contribute to the oxidation state.
The overall charge of the cation is +2.

Let the oxidation state of iron (Fe) be x. Based on the charges of the ligands and the overall cation charge, the equation becomes:

        x + 5(0) + 1 = +2

Solving for x:

        x + 1 = 2
        x = +1

Therefore, the oxidation state of iron (Fe) in the brown ring complex is +1.

The brown ring complex is a unique coordination compound that exhibits interesting chemical properties, making it a classic example in inorganic chemistry studies.

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