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Q.

The brown ring test for nitrites and nitrates is due to the formation of a complex ion with formula:

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a

${[F e {(H_{2} O)}_{5} N O]}^{2 +}$

b

${[F e (N O) {(C N)}_{5}]}^{2 +}$

c

${[F e (H_{2} O) {(N O)}_{5}]}^{2 -}$

d

${[F e {(H_{2} O)}_{6}]}^{2 +}$

answer is A.

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Detailed Solution

in Brown ring test, brown ring is formed due to nitroso ferrous sulphate

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