The bulk modulus of a liquid is 3×108Nm−2. The pressure required to reduce the volume of the liquid by 5% is

B=Δp−Δvv⇒Δp=−BΔvv=3×108×5100=15×106Pa.

The bulk modulus of a liquid is 3×108Nm−2. The pressure required to reduce the volume of the liquid by 5% is

B=Δp−Δvv⇒Δp=−BΔvv=3×108×5100=15×106Pa.

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The bulk modulus of a liquid is $3 \times 10^{8} N m^{- 2} .$ The pressure required to reduce the volume of the liquid by 5% is

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$5 \times 10^{6} N / m^{2}$

$10 \times 10^{6} N / m^{2}$

$15 \times 10^{6} N / m^{2}$

$20 \times 10^{6} N / m^{2}$

answer is C.

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Detailed Solution

$B = \frac{Δ p}{\frac{- Δ v}{v}} \Rightarrow Δ p = - B \frac{Δ v}{v} = 3 \times 10^{8} \times \frac{5}{100} = 15 \times 10^{6} P a .$

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The bulk modulus of a liquid is 3×108Nm−2. The pressure required to reduce the volume of the liquid by 5% is

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The bulk modulus of a liquid is $3 \times 10^{8} N m^{- 2} .$ The pressure required to reduce the volume of the liquid by 5% is