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Q.

The capacitance of an air capacitor is $15 μF$ . The separation between the parallel plates is 6mm. A copper plate of 3mm thickness is introduced symmetrically between the plates. The capacitance now becomes

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a

5 $μF$

b

7.5 $μF$

c

22.5 $μF$

d

30 $μF$

answer is D.

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Detailed Solution

detailed_solution_thumbnail

By using $C_{air} = \frac{ϵ_{0} A}{d}, C_{medium} = \frac{ϵ_{0} A}{d - t + \frac{t}{k}}$
$For K = \infty, C_{medium} = \frac{ϵ_{0} A}{d - t}$

$\Rightarrow \frac{C_{m}}{C_{a}} = \frac{d}{d - t} \Rightarrow \frac{C_{m}}{15} = \frac{6}{6 - 3} \Rightarrow C_{m} = 30 μF$

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