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Q.

The capacities and connection of five capacitors are shown in the adjoining figure. The potential difference between the points A and B is 60 volts. Then the equivalent capacity between A and B and the charge on 5 $μ$ F capacitance will be respectively

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a

15 $μ$ F, 200 $μ$ C

b

44 $μ$ F, 300 $μ$ C

c

16 $μ$ F, 150 $μ$ C

d

4 $μ$ F, 50 $μ$ C

answer is D.

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Detailed Solution

The given circuit can be redrawn as follows
Question Image
Equivalent capacitance of the circuit C_AB = 4 $μ$ F
Charge given by the battery Q = C_eq V = 4 x 60 = 240 $μ$ C
Charge in 5 $μ$ F capacitor $Q^{'} = \frac{5}{(10 + 5 + 9)} \times 240 = 50 μC$

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