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Q.

The capacity of a condenser is 50µF. It is charged to a p.d. of 100 volts by a battery. The distance between the plates is decreased to half by maintaining the battery connection then energy stored
in condenser is

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a

120 × 10–2 J

b

250 × 10–2 J

c

50 × 10–2 J

d

20 × 10–2 J

answer is A.

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Detailed Solution

U=12(2C)V2;U=50×106×104=50×102J

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