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Q.

The capacity of a parallel plate capacitor formed by the plates of same area A is 0.02µF with air as dielectric.  Now one plate is replaced by a plate of area 2A and dielectric (k = 2) is introduced between the plates, the capacity is 

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a

0.04 µF

b

0.01 µF

c

0.08 µF

d

2 µF

answer is A.

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Detailed Solution

detailed_solution_thumbnail

Capacitance of a capacitor with dielectric of dielectric constant k is

C=k∈0Ad=0.02μFC2=2kϵ0Ad=0.04μFcommon area will be A only

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