The carbanion is stabilized by
a) –I effect of CF₃
b) +I effect of CF₃
c) d-orbital resonance of Cl atom

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c only

both b and c

a only

both a and c

answer is C.

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Detailed Solution

In the carbanion ${CF}_{3} - {CCl}_{2}^{⊝}$ , fluorine is more electronegative than Cl and hence, CF₃ exhibits -I effect.
The negative charge, indicating the electrons residing in the empty d-orbital of Chlorine, which participate in resonance to substitute the -I effect of CF₃ group, thus stabilizing the carbanion.

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