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The cartesian equation of the plane passing through (–2, 1, 3) and perpendicular to $3 i + j + 5 k$ is

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3x + y + 5z -10 = 0

3x + y + 5z +10 = 0

3x - y - 5z +10 = 0

3x + y + 5z - 5 = 0

answer is A.

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Detailed Solution

$a = - 2 i + j + 3 k n = 3 i + j + 5 k eq r . n = a . n r . (3 i + j + 5 k) = - 6 + 1 + 15 = 10$

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