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Q.

The cartesian equation of the plane which is is at a distance of 10 units from origin and perpendicular to the vector 2i + 3 j + 6k is

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a

x - 2y -2z = 30

b

2x + 3y + 6z = 70

c

2x + 3y + 6z = 10

d

 x + 2y + 2z = 30

answer is D.

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Detailed Solution

r.n^=d r.(2i+3j+6k)4+9+36=10  2x+3y+6z=70

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