The cell reaction for the given cell is spontaneous if : $Pt; {Cl}_{2} |{Cl}^{-} (1 M) ∥ {Cl}^{- 1} (1 M)| {Cl}_{2}; Pt$

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$P_{1} > P_{2}$

$P_{1} < P_{2}$

$P_{2} = 1 atm$

$P_{1} = P_{2}$

answer is B.

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Detailed Solution

$\begin{array}{l} E_{cell} = E_{{OP}_{Cl}}^{0} + E_{{RP}_{Cl}}^{0} + \frac{0 .059}{2} \log \times \frac{P_{2}}{P_{1}} \\ = \frac{0 .059}{2} \log \frac{P_{2}}{P_{1}} \end{array}$

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