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The cell $Z n / z n^{2 +} (1 M) / / C u^{2 +} (1 M) / C u (E_{c e I I^{0}} = 1.10 V),$ was allowed to be completely discharged at 298K. The relative concentration of ${Zn}^{2+}$ to ${Cu}^{2+}$ is

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$10^{37.3}$

Antilog $(24.04)$

$9.65 \times 10^{4}$

37.3

answer is B.

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Detailed Solution

${Ecell=E}^{0} cell- \frac{0.059}{2} log \frac{[{Zn}^{2+}]}{[{Cu}^{2+}]}$

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