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Q.

The center of the hyperbola  4(2yx3)29(2x+y1)2=80

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a

-15,75

b

25,1310

c

none of these

d

(1,2)

answer is B.

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Detailed Solution

detailed_solution_thumbnail

The equation of the hyperbola is

4(2yx3)29(2x+y1)2=80

The center of the hyperbola is obtained from the equations 

2yx3=0 and 2x+y1=0

Solving, we get, 

 and x=1/5y=7/5

Hence, the center is 15,75

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