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Q.

The centre of mass of a system of three particles of masses 1g , 2g and 3g is taken as the origin of a coordinate system. The position vector of a fourth particle of mass  4g such that the centre of mass of the four particle system lies at the point 1,2,3 is αi+2j+k, where α is a constant. The value of α is :-

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a

52

b

25

c

103

d

12

answer is B.

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Detailed Solution

rcm=m1r1+m2r2+m3r3m1+m2+m3rcm=0 m1r1+m2r2+m3r3=0rcm=m1r1+m2r2+m3r3+m4r4m1+m2+m3+m4(i^+2j^+3k^)=0+4α(i^+2j^+3k^)1+2+3+4α=52

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