The centripetal force required for a 1000 kg car travelling at 36 kmph to take a turn by 900 in travelling along an arc of length 628 m is

As the arc of 90o the length is 628mπ2r=628⇒r=400mF=mv2r=1000x102400=250N

The centripetal force required for a 1000 kg car travelling at 36 kmph to take a turn by 900 in travelling along an arc of length 628 m is

As the arc of 90o the length is 628mπ2r=628⇒r=400mF=mv2r=1000x102400=250N

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The centripetal force required for a 1000 kg car travelling at 36 kmph to take a turn by 90⁰ in travelling along an arc of length 628 m is

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As the arc of 90o the length is 628m

$\frac{π}{2} r = 628 \Rightarrow r = 400 m$

$F = \frac{{mv}^{2}}{r} = \frac{1000 x 10^{2}}{400} = 250 N$

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The centripetal force required for a 1000 kg car travelling at 36 kmph to take a turn by 90⁰ in travelling along an arc of length 628 m is