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Q.

The CFSE for octahedral ${[C o C l_{6}]}^{- 4}$ complex is 18000 cm^-1, then CFSE for tetrahedral ${[C o C l_{4}]}^{- 2}$ will be

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a

$2000 c m^{- 1}$

b

$18000 c m^{- 1}$

c

$8000 c m^{- 1}$

d

$1600 c m^{- 1}$

answer is B.

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Detailed Solution

$Δ_{t} = \frac{4}{9} Δ_{0} = \frac{4}{9} \times 18000 = 8000 c m^{- 1}$

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