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Q.

The change in internal energy of a thermodynamic system which has absorbed 2 kcal of heat and done
400 J of work is (Take, 1 cal = 4.2 J)

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a

5.5 kJ

b

3.5 kJ 

c

2 kJ 

d

8 kJ

answer is B.

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Detailed Solution

According to first law of thermodynamics,

Q=ΔU+W

Q=2kcal=2000×4.2=8400J

W=400J

 8400=ΔU+400

ΔU=8400400

ΔU=8000J

Change in internal energy,  ΔU=8kJ

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