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Q.

The change in the magnitude of the volume of an ideal gas when a small additional pressure ΔP is applied at a constant temperature, is the same as the change when the temperature is reduced by a small quantity ΔT at constant pressure. The initial temperature and pressure of the gas were 300 K and 2 atm respectively. If |ΔT|=C|ΔP| then value of C in (K/atm) is _____________.

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answer is 150.

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Detailed Solution

PV=nRT PΔV+VΔP=O ΔV=VΔPP PΔV=nRΔT ΔV=nRΔTP VΔPP=nRΔTP C=VnR=TP=150

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