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The charge flowing in a conductor varies with time as Q=at-bt². Then, the current

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Increases linearly with time

Reaches a minimum and then increases

Falls to zero at time t=a/2b

Changes at a rate =-2b/a

answer is C.

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Detailed Solution

$I = \frac{dQ}{dt} = a - 2 bt$ . Current decreases linearly with time.

I=0 for t=(a/2b) and (dI/dt)=-2b

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