The charge of an electron is $1.6 \times 10^{- 19}$ coulombs. What will be the value of charge on ${Na}^{+}$ ion

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$11 \times 1.6 \times 10^{- 19} C$

$3.2 \times 10^{- 19} C$

$2.4 \times 10^{- 19} C$

$1.6 \times 10^{- 19}$ C

answer is A.

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Detailed Solution

Explanation:

The charge of a sodium ion (Na⁺) is positive because it has lost one electron. The charge of one electron is 1.6 × 10⁻¹⁹ coulombs, and when a sodium atom loses one electron, the charge on the Na⁺ ion will be equal in magnitude but positive.

Since the magnitude of the charge of a single electron is 1.6 × 10⁻¹⁹ C, the magnitude of the charge on a Na⁺ ion will also be 1.6 × 10⁻¹⁹ C, but it will be positive.

Final Answer

The value of the charge on the Na⁺ ion is +1.6 × 10⁻¹⁹ C.

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