The charge on a capacitor is 30µC. It is connected to another capacitor of half of its capacity in parallel then the charge on the first capacitor is

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9 µC

20 µC

10 µC

30 µC

answer is D.

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Detailed Solution

Q = CV, In parallel, V = constant.
$\begin{array}{l} \frac{Q_{1}}{Q_{2}} = \frac{C_{1}}{C_{2}} = \frac{2}{1}; Q_{1} = \frac{2}{3} Q \\ Q_{2} = \frac{1}{3} Q = \frac{30}{3} = 10 μC; Q_{1} = \frac{2}{3} (30) = 20 μc \end{array}$

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