The charge on capacitor of capacitance 15µF in the figure given below is

$\begin{array}{l}\frac{1}{{\mathrm{C}}_{\mathrm{eq}}}=\frac{1}{10}+\frac{1}{15}+\frac{1}{20}=\frac{12+8+6}{120}=\frac{26}{120}\\ {\mathrm{C}}_{\mathrm{eq}}=\frac{60}{13}\mathrm{\mu F}\\ \mathrm{Q}=\frac{13\times 60}{13}=60\mathrm{\mu C}\end{array}$
Since they are in series, charge on each capacitor is same.