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Q.

The charge per unit length of the four quadrant of the ring is 2λ,2λ,λ and λ respectively. 
The electric field at the center is
 

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a

λ2πε0Ri^

b

λ2πε0Rj^

c

2λ4πε0Ri^

d

None

answer is A.

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Detailed Solution

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Formula: E=λ2πε0Rsinϕ2 (along angle bisector)

Intensity of Electric field due to negative charge =λ4πε0R(i^+j^)
Intensity of electric field due to positive charges =λ4πε0R(i^-j^)

Net electric field=λ2πε0R(i^)

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