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Q.

The charges on two sphere are +7 $μC$ and -5 $μC$ respectively. They experience a force F. If each of them is given and additional charge of -2 $μC$ , the new force of attraction will be:

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a

F

b

F/2

c

F/ $\sqrt{3}$

d

2F

answer is A.

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Detailed Solution

$\begin{array}{l} F = \frac{1}{4 {πε}_{0}} \frac{(+ 7 \times 10^{- 6}) (- 5 \times 10^{- 6})}{r^{2}} \\ = - \frac{1}{4 {πε}_{0}} \frac{35 \times 10^{12}}{r^{2}} N \\ F^{'} = \frac{1}{4 {πε}_{0}} \frac{(+ 5 \times 10^{- 6}) (- 7 \times 10^{- 6})}{r^{2}} \\ = - \frac{1}{4 {πε}_{0}} \frac{35 \times 10^{12}}{r^{2}} N \end{array}$

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