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The chemical reaction between sulphur dioxide gas and gaseous ozone is best represented by the equations as

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$3 {SO}_{2} + O_{3} \to 3 {SO}_{3}$

${SO}_{2} + O_{3} \to {SO}_{3} + O_{2}$

$2 {SO}_{2} + O_{3} \to 2 {SO}_{3} + (O)$

${SO}_{2} + 3 O_{3} \to {SO}_{3} + 4 O_{2}$

answer is A.

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Detailed Solution

$O_{3}$ is an oxidising agent which oxidises others being reduced itself.

So, it oxidises sulphur dioxide to sulphur trioxide by the reaction,

$3 {SO}_{2} + O_{3} \to 3 {SO}_{3}$

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