The chemical reaction
$2 {AgCl}_{(s)} + H_{2 (g)} ⟶ 2 {HCl}_{(aq)} + 2 {Ag}_{(s)}$ t a k i n g place in a galvanic cell is represented by the notation

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${Pt}_{(s)} |H_{2 (g)}, 1 bar| 1 {MHCl}_{(aq)} |{AgCl}_{(s)}| {Ag}_{(s)}$

${Pt}_{(s)} |H_{2 (g)}, 1 bar| 1 {MKCl}_{(aq)} ∥ 1 {MAg}_{(aq)}^{+} ∣ {Ag}_{(s)}$

${Pt}_{(s)} |H_{2 (g)}, 1 bar| 1 {MKCl}_{(aq)} |{AgCl}_{(s)}| {Ag}_{(s)}$

${Pt}_{(s)} |H_{2 (g)}, 1 bar| 1 {MHCl}_{(aq)} |{Ag}_{(s)}| {AgCl}_{(s)}$

answer is C.

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Detailed Solution

The given celll represented as

$P t_{\underset{A n o d e}{(s)}} | H_{2 (g) (1 b a r)} | 1 M H C l_{(a q)} | | A g_{(A q) C a t h o d e}^{+} | A g_{(s)}$

Ag undergoing reduction ( $A g^{+} \to A g$ ), hence it will act as cathode.

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