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The chief ore of zinc is the sulfide, ZnS. The ore is concentrated by a froth floatation process and then heated in air, which converts the ZnS to ZnO.
2ZnS + 3O₂ → 2ZnO + 2SO₂ (75% conversion)
ZnO + H₂SO₄ → ZnSO₄ + H₂O (100% conversion )
2ZnSO₄ + 2H₂O → 2Zn + 2H₂SO₄ + O₂ (80% conversion)
The mass of Zn obtained from a sample of ore containing 292.2 kg of ZnS will be :

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117.72 kg

214.62 kg

145.23 kg

166.55 kg

answer is A.

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Detailed Solution

2ZnS + 3O₂

\to

2ZnO + 2SO₂
2ZnO + 2H₂SO₄

\to

2ZnSO₄ + 2H₂O
2ZnSO₄ + 2H₂O

\to

2Zn + 2H₂SO₄ + O₂
It can be observed that one mole of ZnS gives 1 mole of Zn.
The molar masses of Zn and ZnS are 65.37 g/mol and 97.47 g/mol.
The mass of zinc that can be obtained from
292.2 kg of ZnS is

\frac{65.37}{97.44}

× 292.2 ×

\frac{75}{100}

\frac{100}{100}

\times \frac{80}{100}

=117.72 kg.

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