The chord CB and tangent CP at a point C on the circle intersect at P externally. The value of CP = 6cm, AB = 24cm. then PB?

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15cm

0.5cm

1.5cm

1.51cm

answer is D.

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Detailed Solution

We know that a tangent line to a circle is a line that touches the circle at exactly one point, never entering the circle's interior. The point at which the tangent touches the circle is called the point of contact. The secant of a circle is a line that cuts the circle at two points. The line segment that is formed by the points of intersection is called a chord.
We draw tangent line l whose point of contact is C and secant line mm which makes chord BA in the circle. The tangent and the secant meet at point P. seo

We know from the tangent secant theorem that the square of length the point of contact to the point of intersection of tangent and secant (CP) is equal to the product of the length of the chord (AB) and length of the point of intersection of tangent and the secant to the first point of inspection of secant and the circle (PB). So we have;