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The circle on $S S'$ as diameter intersects the ellipse in real points then

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$e = \frac{1}{\sqrt{2}}$

$e > \frac{1}{\sqrt{2}}$

$e < \frac{1}{\sqrt{2}}$

$e = \frac{1}{2}$

answer is B.

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Detailed Solution

$ae > b \Rightarrow a^{2} e^{2} > b^{2} \Rightarrow a^{2} e^{2} > a^{2} (1 - e^{2}) \Rightarrow e > \frac{1}{\sqrt{2}}$

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