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Q.

The circle orthogonal to the three circles x2 + y2 + ai x + bi y + c = 0, (i = 1, 2, 3) is

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a

x2+y2bixaiyc=0

b

x2+y2=c

c

x2+y2=ai+bi

d

x2+y2=ai

answer is B.

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Detailed Solution

Let S:x2+y2+2gx+2fy+c=0 be a required circle apply the condition 2gg1+2ff1=c+c1  Then required equation of circle is x2+y2=c which cuts given circles orthogonally

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