The circuit shown in the figure contains two diodes each with a forward resistance of 50 ohm and with infinite backward resistance. If the battery voltage is 6 V the current through the 100 ohm resistance (in ampere) is

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zero

0.036

0.02

0.03

answer is B.

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Detailed Solution

$D_{1} i s i n f o r w a r d b i a s D_{2} i s i n r e v e r s e b i a s$

$\begin{array}{l} ε_{net} = 6 v \\ R_{net} = 50 + 150 + 100 = 300 Ω \\ i_{net} = ? \\ i_{net} = \frac{ε_{net}}{R_{net}} = \frac{6}{300} = \frac{6}{3 \times 100} = 2 \times 10^{- 2} A = 0.02 A \\ \dot{i_{net}} = i = 0.02 A \end{array}$

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